Q.
pKa1 and pKa2 of H2SO3 are 1,.82 and 7.20. pH after 20 mL of 0.160 M NaOH is added to 40 mL of 0.080 IM H2SO3 is
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a
7.00
b
1.82
c
8.80
d
4.51
answer is D.
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Detailed Solution
H2SO3+NaOH⇌NaHSO3+H2O 20mL of 0.100MNaOH≡3.2 millimoles of NaOH Thus, H2SO3 is converted into NaHSO3,HSO3−is amphiprotic H+ion donor as well as acceptor) HSO3−⇌H++SO32− HSO3− Base +H+⇌H2SO4 pH=pKa1+pKa22=1.82+7.202=4.51