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Q.

pKa1,pKa2 and pKa3 of H3PO4  are respectively x, y and z. pH of 0.01 M Na2HPO4 solution is

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a

2

b

(x+y2)

c

(y+z2)

d

(x+y+z2)

answer is C.

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Detailed Solution

HPO42− is amphiprotic and it involves pKa2 and pKa3.  HPO42−⇌H++PO43−            Ka3 HPO42−+H+⇌H2PO4− 1Ka2 For such cases, pH=pKa2+pKa32=y+z2
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