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Q.

The plot given below shows P-T curves(where P is the pressure and T is the temperature) for two solvents X and Y and iso-molal solutions of  NaCl in these solvents. NaCl completely dissociates in both the solvents.On addition of equal number  of  moles of a non-volatile solute S in equal amount (in kg) of these solvents, the elevation of boiling point of solvent X is three times that of solvent Y. Solute S is known to undergo dimerization in these solvents. If the degree of dimerization is 0.7 in solvent Y, the degree of dimerization in solvent X is        .

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answer is 0.05.

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Detailed Solution

From the  graph we can observe thatFor solvent X’      ΔTbx=2ΔTbx=mNaCl×Kb(x)  ……….(1)            For solvent ‘Y’          ΔTby=1 ΔTby=mNaCl×Kby ……….(2)         Equation (1) /(2)⇒KbxKby=2             For solute S2(S)→S21−αα/2i=(1−α/2)ΔTb(x)(s)=1−α12Kb(x) ΔTb(x)(s)=1−α22Kb(y) Given ΔTb(x)(s)=3ΔTb(y)(s)1−α12Kb(x)=3×1−α22×Kb(y)    21−α12=31−α22α2=0.7    So α1=0.05
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The plot given below shows P-T curves(where P is the pressure and T is the temperature) for two solvents X and Y and iso-molal solutions of  NaCl in these solvents. NaCl completely dissociates in both the solvents.On addition of equal number  of  moles of a non-volatile solute S in equal amount (in kg) of these solvents, the elevation of boiling point of solvent X is three times that of solvent Y. Solute S is known to undergo dimerization in these solvents. If the degree of dimerization is 0.7 in solvent Y, the degree of dimerization in solvent X is        .