The plot given below shows P-T curves(where P is the pressure and T is the temperature) for two solvents X and Y and iso-molal solutions of NaCl in these solvents. NaCl completely dissociates in both the solvents.On addition of equal number of moles of a non-volatile solute S in equal amount (in kg) of these solvents, the elevation of boiling point of solvent X is three times that of solvent Y. Solute S is known to undergo dimerization in these solvents. If the degree of dimerization is 0.7 in solvent Y, the degree of dimerization in solvent X is .
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answer is 0.05.
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Detailed Solution
From the graph we can observe thatFor solvent X’ ΔTbx=2ΔTbx=mNaCl×Kb(x) ……….(1) For solvent ‘Y’ ΔTby=1 ΔTby=mNaCl×Kby ……….(2) Equation (1) /(2)⇒KbxKby=2 For solute S2(S)→S21−αα/2i=(1−α/2)ΔTb(x)(s)=1−α12Kb(x) ΔTb(x)(s)=1−α22Kb(y) Given ΔTb(x)(s)=3ΔTb(y)(s)1−α12Kb(x)=3×1−α22×Kb(y) 21−α12=31−α22α2=0.7 So α1=0.05
The plot given below shows P-T curves(where P is the pressure and T is the temperature) for two solvents X and Y and iso-molal solutions of NaCl in these solvents. NaCl completely dissociates in both the solvents.On addition of equal number of moles of a non-volatile solute S in equal amount (in kg) of these solvents, the elevation of boiling point of solvent X is three times that of solvent Y. Solute S is known to undergo dimerization in these solvents. If the degree of dimerization is 0.7 in solvent Y, the degree of dimerization in solvent X is .