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Q.

Plot of log (x/m) against log P is a straight line inclined at an angle of450 When the pressure is 0.5 atm and Freundlich parameter k is 10, the amount of soluteadsorbed per gram of adsorbent will be (log 5 : 0.6990):

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a

1 g

b

2 g

c

3 g

d

5 g

answer is D.

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Detailed Solution

According to Freundlich adsorption isotherm:log⁡xm=log⁡k+1nlog⁡PWhen log (xlm) is plotted against Log P, we get straight line of slope (lln) and intercept (log k).1n=tan⁡45∘=1log⁡k=log⁡10=1xm=k(P)1/n=10(0.5)1=5
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