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In the formal charge on each oxygen atom and bond order respectively are
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By Expert Faculty of Sri Chaitanya
a
−0.75,1.25
b
−0.75,1.0
c
−0.75,0.6
d
−3,1.25
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Correct option is A
Bond order = Total number of bonds between atoms Total number of resonating structure Bond order =5/4=1.25In a given resonance structure, the O atom that forms double bond has formal charge of 0 and the remaining 3 O atoms have formal charge of -1 each.In the resonance hybrid, a total of -3 charge is distributed over four O atoms. Thus the formal charge of each O atom = −3/4 = −0.75.Similar Questions
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