The polymerization of ethylene to linear polythene is represented by the reactionnCH2=CH2→-(CH2-CH2)- nWhere n has a large integral value. Given that the average enthalpies of bond dissociation for c=c and c-c at 298 K are +590 and +331 kJ/mol respectively. Calculate the enthalpy of polymerisation per mole of ethylene at 298 K (neglect sign) __________
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answer is 72 KJ/MOL.
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Detailed Solution
During polymerization of ethylene c=c double bond breaks and two C-H single bonds are formed. In the whole polymer unit the number of single bonds formed per mole of ethylene are two. Energy absorbed due to dissociation of one c=c bond = 590 kJ/mol Energy released due to formation of two c-c single bonds = 2x331 = 662 kJ/mol ΔH polymerization = 590-662 = -72 kJ/mol