The position of both an electron and a helium atom is known within 1.0 nm and the momentum of the electron is known within 50 × 10−26 kg ms−1. The minimum uncertainty in the measurement of the momentum of the helium atom is

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50 kg ms−1

60 kg ms−1

80 × 10−26 kg ms−1

50 × 10−26 kg ms−1

answer is D.

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Detailed Solution

The product of uncertainties in the position and the momentum of a sub atomic particle = h/4π. Since Δx is same for electron and helium so Δp must be same for both the particle, i.e., 50 × 10−26 kg ms−1 (given).

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