Q.
The possible value of l and m for the last electron in the Cl− ion are
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a
1 and 2
b
2 and + 1
c
3 and -1
d
1 and -1
answer is D.
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Detailed Solution
Cl17− : Ne3s2 3p6.Last electron enters 3p orbital.∴ l=1 and m=1, 0,−1.
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