Q.

The possible value of l and m for the last electron in the Cl− ion are

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a

1 and 2

b

2 and + 1

c

3 and -1

d

1 and -1

answer is D.

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Detailed Solution

Cl17− :  Ne3s2 3p6.Last electron enters 3p orbital.∴   l=1  and  m=1,  0,−1.
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