Q.

Potassium chlorate is prepared by the electrolysis of KCl in basic solution 6OH−+Cl−→ClO3−+3H2O+6e−.  If only 60% of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce 10g of KClO3 using a current of 2 A is______(Given : F=96,500 C mol−1; molar mass of KClO3=122    g   mol−1)

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answer is 11.

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Detailed Solution

6OH−+Cl−→ClO3−+3H2O+6e−For 6×96500C→122gKClO3Q →10gKClO3Q=579×104122=47459 Actural current used (i) =0.6×2=1.2Q=i×t⇒474591.2=t ⇒t=39549.2sect=11 hours
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Potassium chlorate is prepared by the electrolysis of KCl in basic solution 6OH−+Cl−→ClO3−+3H2O+6e−.  If only 60% of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce 10g of KClO3 using a current of 2 A is______(Given : F=96,500 C mol−1; molar mass of KClO3=122    g   mol−1)