Q.

The potential of the cell containing two hydrogen electrodes as represented below Pt, H2(g) | H+ (10-6M) || H+(10-4M)|H2(g), Pt at 298 K is

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a

– 0.118 V

b

– 0.0591 V

c

0.118 V

d

0.0591 V

answer is C.

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Detailed Solution

cell representation Pt,H2(g)/H+10-6M//H+10-4M/H2(g),PtCell reaction H2(1atm)+2H+10-4M→2H+10-6M+H2(1atm)Applying Nernst equationEcell=Ecello-0.05912log10-6210-42;Ecell=0+4×0.05912=+0.1182 V
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The potential of the cell containing two hydrogen electrodes as represented below Pt, H2(g) | H+ (10-6M) || H+(10-4M)|H2(g), Pt at 298 K is