First slide

Nernst Equation

Question

The potential of hydrogen electrode is –118 mV. The H⁺ concentration of the solution is

Easy

Solution

${p^H} = \frac{{ - {E_{RP}}}}{{0.0591}} \Rightarrow \log \left[ {{H^ + }} \right] = \frac{{{E_{RP}}}}{{0.0591}}$

$\left[ {{H^ + }} \right] = {10^{\frac{{ - 0.118}}{{0.0591}}}} = {10^{ - 2}}$

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