In the presence of excess of anhydrous SrCl2 , the amount of water taken up is governed by Kp=1012 atm−4 for the following reaction at 273 K SrCl2.2H2O(s)+4H2O(g)⇌SrCl2.6H2O(s) What is equilibrium vapour pressure (in torr) of water in a closed vessel that contains SrCl2.2H2O(s) ?

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0.001 torr

103 torr

0.76 torr

1.31 torr

answer is C.

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Detailed Solution

KP=1PH2O(g)4 ⇒PH2O(g)=(1KP)1/4 ⇒(10−12)1/4=10−3 atm ∴ KP=10−3×760=0.76 torr

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