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Q.

Pressure exerted by 1 mole of methane in a 0.25 litre container at 300 K using van der Waals' equation (given a = 2.253 atm L2 mol-2, b= 0.0428 L mol-1) is

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Detailed Solution

P+ n2aV2 V-nb = nRT P+2.2530.25 × 0.25 0.25-0.428=0.0821 × 300 or P+36.048 0.2072=24.63 ⇒P+36.075 = 118.87          ⇒ P = 82.82 atm
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Pressure exerted by 1 mole of methane in a 0.25 litre container at 300 K using van der Waals' equation (given a = 2.253 atm L2 mol-2, b= 0.0428 L mol-1) is