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Surface phenomenon

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By Expert Faculty of Sri Chaitanya
Question

The pressure of the gas decreases from 380 mm of Hg to 190 mm of Hg. When 50 gm of sample of activated charcoal was kept in a flask of 1 lit capacity at T k. The volume of gas adsorbed per gram of charcoal at 190 mm of Hg at same T k  is ----------------ml

Moderate
Solution

n = pvRT

number of moles adsorbed = n1 - n21RT380760-190760=0.25RT

VadsorbednadsorbedRTp(atm)=0.25RT×RT190760=1lit

Vadsorbed per gram of char coal  = 150 = 0.02 lit = 0.02×1000 =20 ml


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