Download the app

Surface phenomenon

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
Question

The pressure of the gas decreases from 380 mm of Hg to 190 mm of Hg. When 50 gm of sample of activated charcoal was kept in a flask of 1 lit capacity at T k. The volume of gas adsorbed per gram of charcoal at 190 mm of Hg at same T k  is ----------------ml

Moderate
Solution

n = pvRT

number of moles adsorbed = n1 - n21RT380760-190760=0.25RT

VadsorbednadsorbedRTp(atm)=0.25RT×RT190760=1lit

Vadsorbed per gram of char coal  = 150 = 0.02 lit = 0.02×1000 =20 ml


NEW

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


ctaimg

Create Your Own Test
Your Topic, Your Difficulty, Your Pace


ctaimg

Similar Questions

When a graph is plotted between logx/m and logp it is straight line with an angle 45° and intercept 0.3010 on y - axis . If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent 

Get your all doubts cleared from
Sri Chaitanya experts

counselling
india
+91

phone iconwhats app icon