Q.

The pressure of H2 required to make the potential of H2 electrode zero in pure water at 298 K

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answer is 3.

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Detailed Solution

pH=7 for pure water because it is neutral. -logH+=7⇒H+=10-72H(aq)++2e-⟶H2( g)Ecell =Ecell °-0.05912logpH2H+20=0-0.05912logpH210-72logpH210-72=0⇒pH210-72=1 [∵log1=0]pH2=10-14 atm

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