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Pressure of H2 required to make the potential of hydrogen-electrode zero in pure water at 298 K is:

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By Expert Faculty of Sri Chaitanya
a
10-14 atm
b
10-12 atm
c
10-10 atm
d
10-4 atm

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detailed solution

Correct option is A

2H+(aq)+2e−→H2(g)∴E=E0−0.05912log⁡PH2H+20=0−0.0295log⁡PH210−72PH210−72=1PH2=10-14 atm
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