First slide

Nernst Equation

Question

Pressure of H₂ required to make the potential of hydrogen-electrode zero in pure water at 298 K is:

Moderate

A

10^-14 atm
B

10^-12 atm
C

10^-10 atm
D

10^-4 atm

Solution

$\begin{array}{l} 2 H^{+} (aq) + 2 e^{-} \to H_{2} (g) \\ ∴ E = E^{0} - \frac{0 .0591}{2} \log \frac{P_{H_{2}}}{{[H^{+}]}^{2}} \\ 0 = 0 - 0 .0295 \log \frac{P_{H_{2}}}{{(10^{- 7})}^{2}} \\ \frac{P_{H_{2}}}{{(10^{- 7})}^{2}} = 1 \\ P_{H_{2}} = 10^{- 14} atm \end{array}$

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