Pressure of H2 required to make the potential of hydrogen-electrode zero in pure water at 298 K is:

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10-14 atm

10-12 atm

10-10 atm

10-4 atm

answer is A.

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Detailed Solution

2H+(aq)+2e−→H2(g)∴E=E0−0.05912log⁡PH2H+20=0−0.0295log⁡PH210−72PH210−72=1PH2=10-14 atm

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