Q.

The pressure and temperature of 4dm3 of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be

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a

2 dm3

b

3 dm3

c

4 dm3

d

8 dm3

answer is C.

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Detailed Solution

P1V1T1=P2V2T2;P1×4T1=2P1×V22T18=2 x V2 so V2=4dm3
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