The process is called N - acylation of aniline. The correct reactivity order for this reaction when ‘X’ is.
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
(CH3CO)2O>CH3COCl>CH3COOC2H5
b
CH3COOC2H5>CH3COCl>(CH3CO)2O
c
(CH3CO)2O>CH3COOC2H5>CH3COCl
d
CH3COCl>(CH3CO)2O>CH3COOC2H5
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
C6H5-NH-H+Z-CO||-CH3→pyridineC6H5NH-CO||-CH3+HZ-Z is the leaving groupLeaving group ability of -Cl > -OCOCH3 > -OC2H5Leaving group ability ∝1basic strengthAcidic strength of HCl > CH3COOH > C2H5OHBasic strength of Cl- < CH3COO- < C2H5O- .