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# For the process  at 750 K the value of equilibrium constant is  ${10}^{2}$. At 450K the value of equilibrium constant for the same reaction is $5×{10}^{2}.$ Correct statement about the process is

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a
Addition of ‘A’ has no effect on equilibrium state
b
Removal of ‘C’ has no effect on equilibrium state
c
Pressure has no effect on equilibrium state
d
Formation of ‘C’ is an exothermic process

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detailed solution

Correct option is D

Addition or removal of gaseous  reactant or product always influences the equilibrium state .∆ng< 0...... high pressure favours forward reaction .When temperature increases, Keq decreases for an exothermic reactions .

Similar Questions

Consider the following reactions
$\begin{array}{l}\mathrm{A}⇌2\mathrm{B};\mathrm{K}=10\dots \left(\mathrm{I}\right)\\ \mathrm{B}⇌\mathrm{C};\mathrm{K}=2\dots \left(\mathrm{II}\right)\end{array}$
Equilibrium constant for $2\mathrm{C}⇌\mathrm{A}$ will be

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