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The Prussian blue colouration obtained in the test for nitrogen in the organic compound is
 

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By Expert Faculty of Sri Chaitanya
a
K4[Fe(CN)6]
b
Fe4[Fe(CN)6]3
c
Fe[Fe(CN)6]
d
Fe3[Fe(CN)6]2

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detailed solution

Correct option is B

4Fe3+ + 3Na4[Fe(CN)6] → Fe4[Fe(CN)6]3 + 12Na+                                               (Prussian blue)Hence, the correct answer is (2).


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