First slide

Qualitative analysis

Question

Prussian blue is formed when:

Moderate

A

$Ferrous sulphate reacts with {FeCl}_{3}$
B

$Ferric sulphate reacts with K_{4} [Fe (CN)_{6}]$
C

$Ferrous ammonium sulphate reacts with {FeCl}_{3}$
D

$Ammonium sulphate reacts with {FeCl}_{3}$

Solution

$2 {Fe}_{2} {({SO}_{4})}_{3} + 3 K_{4} [Fe (CN)_{6}] ⟶ {Fe}_{4} {[Fe (CN)_{6}]}_{3} + 6 K_{2} {SO}_{4} Prussian blue$

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