PtCI4.6H2O can exist as a hydrated complex; 1 m aqueous solution has the depression in freezing point of 3.72 K. Assume 100% ionization and Kf(H2O) = 1.86 Km-1, then the complex is

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[Pt(H2O)6]CI4

[Pt(H2O)4+Cl2]CI2.2H2O

[Pt(H2O)3CI3]Cl.3H2O

[Pt(H2O)2CI4].4H2O

answer is C.

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Detailed Solution

∆Tf=Molality×Kf×i 3.72=1×1.86×i i=2, hence complex is binary Also, C.N of Pt is 6 and complex is hydrated.

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