Q.

Pure PCl5 is introduced into an evacuated chamber and comes to equilibrium at 247oC and 2.0 atm. The equilibrium gaseous mixture contains 40% chlorine by volume. Calculate Kp at 247∘C for the reaction PCl5(g)⇌PCl3(g)+Cl2(g)

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

0.625atm

4atm

1.6atm

None of these

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The gaseous mixture contains 40% Cl2 and 40% PCl3, since they are produced in 1 : 1 mole ratio. The PCl5% is 20 For ideal gases, mole % = volume%PCl2=PPCl3 PPCl3=nPCl3n×P=0.41×0.2= 0.80 atm PPCl5=2×0.2=0.40 atm Kp=PPCl3·PCl2PPCl5 =0.80×0.800.40=1.6 atm

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET