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Q.

In pyranose of glucose oxide (ether) linkage is formed between

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a

C1 and C6

b

C2 and C6

c

C1 and C5

d

C2 and C5

answer is C.

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Detailed Solution

Pyranose ring structure of glucose is due to hemiacetal formation between  C1​ and C5​ carbon atoms. In general, a pyranose is any cyclic isomer that has a five carbon atoms and one oxygen atom in a ring of six atoms.
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