In pyranose of glucose oxide (ether) linkage is formed between
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a
C1 and C6
b
C2 and C6
c
C1 and C5
d
C2 and C5
answer is C.
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Detailed Solution
Pyranose ring structure of glucose is due to hemiacetal formation between C1 and C5 carbon atoms. In general, a pyranose is any cyclic isomer that has a five carbon atoms and one oxygen atom in a ring of six atoms.