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Q, P, A, X and E are the elements belonging to 14th group of Modern periodic table. The correct trend of ionization potential for these elements is Q > P > A > X > E . The element ‘E' in the sequence is

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a

Pb

b

Si

c

Sn

d

Ge

answer is C.

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Detailed Solution

Atomic radius trend…CSi>Ge>Pb>Sn;EN trend…C>Pb>Si=Ge=Sn;Density…..C(graphite)Si>Ge>Sn>Pb;Resistivity…C>Si=Ge>Pb>Sn;Conductivity…C

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