First slide

Electrolysis

Question

$A q u e o u s s o l u t i o n o f A g N O_{3} i s e l e c t r o l y s e d u \sin g P t e l e c t r o d e s . P r o d u c t s o b t a i n e d a t a n o d e a n d c a t h o d e r e s p e c t i v e l y$

Moderate

A

$A g, {O_{2}}_{}$
B

$A g, N {O_{2}}_{}$
C

$O_{2}, A g$
D

$H_{2}, O_{2}$

Solution

At cathode
$E_{A g^{+} / A g}^{o} > E_{H^{+} / \frac{1}{2} H_{2}, P t}^{o}$
$∴ [A g^{+} + e^{-} \to A g ↓] \times 4$
At anode
$S R P o f N O_{3}^{-} / N O_{2}, N O_{3}^{-} / N O a r e h i g h$
$E_{O_{2} / H_{2} O}^{o} < E_{N O_{3}^{-} / N O_{x}}^{o}$
$(o r) S O P o f E_{H_{2} O / O_{2}}^{o} > E_{N O_{x} / N O_{3}^{-}}^{o}$
$2 H_{2} O \to 4 H^{+} + 4 e^{-} + O_{2}$

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