The quantity of charge liberated during the formation of 3.6 grams of water in hydrogen fuel cell is
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Detailed Solution
Fuel cell reaction:Net reaction : 2H2 + O2 → 2H2O Note : Electrolysis of water2H2O → 2H2 + O2At Anode : 2H2 → 4H+ + 4e- → In the formation of 2 moles of H2O transfer of 4moles of e-s takes place.At Cathode :→ 36gr of H2O → 4f3.6gr of H2O → ??3.6×436=0.4 F