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Hydrogen as a fuel

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By Expert Faculty of Sri Chaitanya
Question

The quantity of charge liberated during the formation of 3.6 grams of water in hydrogen fuel cell is

Easy
Solution

Fuel cell reaction:

Net reaction : 2H2 + O2 → 2H2O 

                                 2×18=36

 Note : Electrolysis of water

2H2O → 2H2 + O2

At Anode : 2H2 → 4H+ + 4e- → In the formation of 2 moles of H2O transfer of 4moles of e-s takes place.

At Cathode :

\large \frac{{4{H^ + } + 4{e^ - } + {O_2} \to 2{H_2}O}}{{2{H_2} + {O_2} \to 2{H_2}O}}\

→ 36gr of H2O → 4f

3.6gr of H2O → ??

3.6×436=0.4 F


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