First slide

Gaseous state

Question

A quantity of gas is collected in a graduated tube over the mercury. The volume of the gas at 20°C is 50.0 mL and the level of the mercury in the tube is 100 mm above the outside mercury level. The barometer reads 750 mm. Volume at STP is

Moderate

A

39.8 mL
B

40 mL
C

42 mL
D

60 mL

Solution

$(p_{2}) resultant pressure = (750 - 100) = 650 mm$
$(T_{2}) temperature = 293 K (V_{2}) volume = 50 .0 mL at STP T_{1} = 273 K p_{1} = 760 mm, V_{1} = ? \Rightarrow \frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}} ∴ V_{1} = 39 .8 mL$

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