A quantity of hydrogen gas occupies a volume of 30.0 mL at a certain temperature and pressure. What volume would half this mass of hydrogen occupy at triple the absolute temperature if the pressure were one-ninth that of the original gas?

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27O mL

90 mL

405 mL

135 mL

answer is C.

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Detailed Solution

p1V1=n1RT1 p2V2=n2RT2 ⇒ p19V2=n12R3T1 n1RT1V1V29=n12R3T1 ∴ V2=27V12=13.5×30mL=405mL

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