Quantity of work (in joules) done by the gas if it expands against a constant pressure of 0.980 atm and the change in volume (∆V) is 25.0 L, is

Work done - p∆V=0.980 atm×25.0 L=24.5 L atm=24.5 L atm×8.314 J mol−1K−10.0821 L atm mol−1K−1=2481J=2.481×103JNote Use value of R (gas constant to convert L atm to JR=0.0821 L atm mol−1 K−1=8.314 J mol−1 K-1