R−OH →Z R−ClPure. Z in the process is

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PCl3

PCl5

HCl + anhydrous ZnCl2

SOCl2

answer is D.

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Detailed Solution

R−OH +SOCl2→ether R−Cl+SO2+HCl.HCl and SO2 being gases escape out leaving behind pure Alkyl halide.

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