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Q.

R−OH   →Z   R−ClPure. Z in the process is

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a

PCl3

b

PCl5

c

HCl + anhydrous ZnCl2

d

SOCl2

answer is D.

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Detailed Solution

R−OH +SOCl2→ether  R−Cl+SO2+HCl.HCl and SO2 being gases escape out leaving behind pure Alkyl halide.
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