The radii of two of the first four Bohr’s orbits of the hydrogen atoms are in 1:4 ratio . The energy difference between them may be

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either 12.09 eV or 3.4eV

either 2.55eV or 10.2eV

either 13.6eV or 3.4eV

either 3.4 eV or 0.85eV

answer is B.

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Detailed Solution

Radius of orbit αn2 if n = 1 & n = 2r1 : r2 = 1 : 4similarly n = 2 & n = 4r2 : r4 = 4 : 16 = 1 : 4E2 - E1 = 10.2 ev/atomE4 - E2 = 2.55 ev/atom

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