A radioactive sample has initial activity of 28 dpm, 30 minutes later its activity is l4 dpm. How many atoms of nuclide were present initially?

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2800

1212

528

2802

answer is B.

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Detailed Solution

A0=KN028=ln⁡230×N028=2.3×log⁡2×N030(log⁡2=0.3)N0=30×282.3×0.3=1217.4