Q.

In a radioactive series, a radioactive isotope decays to stable isotope.  90232Th decays by emission of six α and four β -particles. Stable isotope is

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a

Pu-256

b

Th-232

c

Rn−220

d

Pb-208

answer is D.

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Detailed Solution

90232Th⟶−6α78208X⟶−4β82208Pb
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