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Q.

Radioactivity of a radioactive element remains 1/10 of the original radioactivity after 2.303 seconds. The half life period is

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a

2.303

b

0.2303

c

693

d

0.693

answer is D.

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Detailed Solution

K=2.303tlog⁡aa−x t=2.303 (given) (a−x)=110a0=2.303tlog⁡11/10=1∴t1/2=0.693K=0.6931=0.693
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