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Q.

Radius of fifth orbit in Be+3 ion is n ×r0. Value of n is equal to  (ro= Bohr's radius = radius of first orbit in H-atom)

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a

0.31

b

0.8

c

1.25

d

6.25

answer is D.

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Detailed Solution

rn=n2Zro; r5Be+3, Z=4=524×r0
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