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Q.

Radius of fifth orbit in He+ ion is n ×r0. Value of n is equal to  (ro= Bohr's radius = radius of first orbit in H-atom)

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a

0.4

b

12.5

c

0.08

d

2.5

answer is B.

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Detailed Solution

rn=n2Zro; r5He+, Z=2=522×r0
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