Q.
Radius of fifth orbit in Li2+ ion is n ×r0. Value of n is equal to (ro= Bohr's radius = radius of first orbit in H-atom)
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a
8.33
b
0.6
c
0.12
d
1.66
answer is A.
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Detailed Solution
rn=n2Zro; r5Li2+, Z=3=523×r0
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