Q.

Radius of fifth orbit in Li2+ ion is n ×r0. Value of n is equal to  (ro= Bohr's radius = radius of first orbit in H-atom)

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a

8.33

b

0.6

c

0.12

d

1.66

answer is A.

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Detailed Solution

rn=n2Zro; r5Li2+, Z=3=523×r0
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