Q.

Radius of fourth orbit in Li2+ ion is n ×r0. Value of n is equal to  (ro= Bohr's radius = radius of first orbit in H-atom)

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a

0.187

b

0.44

c

5.33

d

1.33

answer is C.

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Detailed Solution

rn=n2Zro; r4Li2+, Z=3=423×r0
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