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Q.

Radius of third orbit in He+ ion is n ×r0. Value of n is equal to  (ro= Bohr's radius = radius of first orbit in H-atom)

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a

0.66

b

1.33

c

1.5

d

4.5

answer is D.

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Detailed Solution

rn=n2Zro; r3He+, Z=2=322×r0
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