The radius of which of the following orbit is same as that of the first Bohr's orbit of hydrogen atom.
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a
He+ n=2
b
Li2+ n=2
c
Li2+ n=3
d
Be3+ n=2
answer is D.
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Detailed Solution
rn=0.529 n2Z AoFor hydrogen, n = 1 and Z = 1; ∴ rH=0.529For He+ , n=2 and Z=2 ∴ rHe+ =0.529×42 For Li+2 , n =2 and z=3 ∴ rLi+2 =0.529×43 For Li+2 , n=3 and z=3 ∴ rLi+2 = 0.529×93 For Be3+, n=2 and Z=4∴ rBe3+ = 0.529 × 224=0.529 (which is same as r1 of H-atom)