The rate of a certain biochemical reaction at physiological temperature (T) occurs 106 times faster with enzyme than without. The change in the activation energy upon adding enzyme is:
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a
+6(2.303)RT
b
+6RT
c
-6(2.303)RT
d
-6RT
answer is C.
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Detailed Solution
k2k1=eEa1-Ea2/RT106=e−Ea 1~Ea2RT∆Ea=(-2.303×6×R×T)i.e. Energy of activation decreases by (6×2.303RT).