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Q.

The rate constant, the activation energy and the Arrhenius parameter of a chemical reaction at 25oC are 3.0×10−4s−1, 104.4 kJ mol−1 and 6.0×1014s−1 respectively. The value of the rate constant as T→∞ is

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a

2.0×1018s−1

b

6.0×1014s−1

c

Infinity

d

3.6×1030s−1

answer is B.

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Detailed Solution

T2=T(say), T=25oC=298 K,Ea=104.4 kJ mol−1=104.4×103 J mol−1K1=3×10−4,K2=?log⁡K2K1=Ea2.303R[1T1−1T2]log⁡K23×10−4=104.4×103 J mol−12.303×(8.314 J k−1 mol−1)1298K-1T      As T→∞,1T→0∴ log⁡K23×10−4=104.4×103 J mol−12.303×8.314×298log⁡K23×10−4=18.297, K23×10-4=1.98×1018 K2=(1.98×1018)×(3×10−4)=6×1014s−1                                                    (OR) K=Ae−Ea/RTAs T→∞K=A⇒ 6×1014 sec−1
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