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Q.

The rate constant for the first order decomposition of a certain reaction is described by the equation In k(sec-1) = 14.34-1.25×104T. The energy of activation for this reaction is

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answer is 4.

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Detailed Solution

lnA-EaRT=14.34-1.25×104T Ea2 cal×T=1.25×104T Ea=2×1.25×104=2.5×104 cal/mole

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