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Q.

The rate constant for a first order reaction is 4.606 x 10-3 s-1. The time required to reduce 2.0 g of the reactant to 0.2 g is

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a

1000 s

b

100 s

c

200 s

d

500 s

answer is D.

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Detailed Solution

k=4.606×10−3s−1kt=2.303log10⁡20.24.606×10−3×t=2.303×log⁡10t=10002=500s.
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