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Q.

The rate constant for forward and backward reactions of hydrolysis of ester are 1.1× 10-2and 1.5× 10-3 per minute respectively. Equilibrium constant for the reaction is

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a

4.33

b

5.33

c

6.33

d

7.33

answer is D.

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Detailed Solution

Kf=1.1 × 10-2;  Kb=1.5 × 10-3 Kc=KfKb=1.1 × 10-21.5 × 10-3=7.33
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The rate constant for forward and backward reactions of hydrolysis of ester are 1.1× 10-2and 1.5× 10-3 per minute respectively. Equilibrium constant for the reaction is