Q.
The rate constant for forward reaction A(g)⇌2B(g) is 1.5×10−3s−1 at 100K. If 10-5 moles of A and 100 moles of B are present in a 10-L vessel at equilibrium, then therate constant for the backward reaction at this temperature is
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a
1.50×10-4 L mo−1s-1
b
1.50×10−11Lmol−1s−1
c
1.50×10−10Lmol−1s−1
d
None of these
answer is B.
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Detailed Solution
keq=[B]2[A]=[100/10]210−5/10=108keq=kfkb⇒kb=1.5×10−3108=1.5×10−11Lmol−1s−1
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