The rate constant k, for the reaction N2O5(g)→2NO2(g)+12O2(g) is 2.3×10−2s−1. Which equation given below describes the change of [N2O5] with time? [N2O5]0 and [N2O5]t correspond to concentration of N2O5 initially and at time, t?

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[N2O5]t=[N2O5]0+kt

[N2O5]0=[N2O5]tekt

log⁡10[N2O5]t=log⁡10[N2O5]0−kt

ln⁡[N2O5]0[N2O5]t=kt

answer is D.

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Detailed Solution

Rate constant=2.3×10−2sec⁡−1It means it is a first order reaction (because unit of rate constant is sec-1)For first order reaction k=1tln⁡aa−xkt=ln⁡aa−x=ln⁡[N2O5]0[N2O5]t

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