The rate constant k, for the reaction $$N2O5(g)$$→$$2NO2(g)+12O2(g)$$ is $$2.3$$×$$10$$−$$2s$$−$$1$$. Which equation given below describes the change of [$$N2O5$$] with time? [$$N2O5$$]$$0$$ and [$$N2O5$$]t correspond to concentration of $$N2O5$$ initially and at time, t?

Question

The rate constant k, for the reaction $$N2O5(g)$$→$$2NO2(g)+12O2(g)$$ is $$2.3$$×$$10$$−$$2s$$−$$1$$. Which equation given below describes the change of [$$N2O5$$] with time? [$$N2O5$$]$$0$$ and [$$N2O5$$]t correspond to concentration of $$N2O5$$ initially and at time, t?

Infinity Learn · Accepted Answer

Rate $$constant=2.3$$×$$10$$−$$2sec$$⁡−$$1It$$ means it is a first order reaction $$(because$$ unit of rate constant is $$sec$$$$-1)For$$ first order reaction $$k=1tln$$⁡aa−$$xkt=ln$$⁡aa−$$x=ln$$⁡[$$N2O5$$]$$0$$[$$N2O5$$]t

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The rate constant k, for the reaction N2O5(g)→2NO2(g)+12O2(g) is 2.3×10−2s−1. Which equation given below describes the change of [N2O5] with time? [N2O5]0 and [N2O5]t correspond to concentration of N2O5 initially and at time, t?

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