The rate constant of a reaction increases by five times on increase in temperature from 27°C to 52°C. The value of activation energy in KJ mol−1is……… (Rounded off to the nearest integer) [R =8.314 Jk−1 mol−1 ]

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answer is 52.

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Detailed Solution

log51 =Ea2.303×8.314 25300×325Ea=0.7×2.303×8.314×300×32525×100. Ea=52.27KJ

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