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Q.

Rate of diffusion of NH3 is twice that of X. What is the molecular mass of X

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a

68

b

48

c

12

d

8

answer is A.

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Detailed Solution

Rate of diffusion, rX=rNH32 (given)Molecular mass of NH3, MNH3=(N)+3(H)                                                =14+3(1)=17Molecular mass of X, Mx = ? By Graham's law of diffusion∴rNH3rX=MXMNH3 or 2=MXMNH3∴4×MNH3=MX⇒MX=4×17=68.
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